Explain how System 1 becomes equivalent to System 2. System 1:

Ax + By = C

Lx + My = N

System 2:

Ax + By = C

(A − L)x + (B − M)y = C − N

The first equation in System 1 is the sum of the equations in System 2. The second equation in System 2 is the first equation in System 2.

The first equation in System 1 is the difference of the equations in System 2. The second equation in System 1 is the first equation in System 2.

The second equation in System 2 is the sum of the equations in System 1. The first equation in System 2 is the first equation in System 1.

The second equation in System 2 is the difference of the equations in System 1. The first equation in System 2 is the first equation in System 1.

my guess is

step-by-step explanation:

answer: 8

step-by-step explanation:

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.