Solve the equation by completing the square 3s^2+8s=2s-9

S=
S=

I need this to be answer ASAP and with a step by step explanation please !

x = - 1 ± i

Step-by-step explanation:

Given

3s² + 8s = 2s - 9 ( subtract 2s - 9 from both sides )

3s² + 6s + 9 = 0

To complete the square

The coefficient of the s² term must be 1, so factor out 3 from 3s² + 6s

3(s² + 2s) + 9 = 0

add/subtract ( half the coefficient of the s- term )² to s² + 2s

3(s² + 2(1)s + 1 - 1) + 9 = 0

3(s + 1)² - 3 + 9 = 0

3(s + 1)² + 6 = 0 ( add 6 to both sides )

3(s + 1)² = - 6 ( divide both sides by 3 )

(s + 1)² = - 2 ( take the square root of both sides )

s + 1 = ± = ± i ( subtract 1 from both sides )

s = - 1 ± i

Thus

s = - 1 + i , s = - 1 - i

answer: the answer to your question is parallel