Write the slope-intercept form of an equation of the line that passes through the given point and is parallel to the graph of each equation: (-8,2) 5x - 4y = 1

slope(m)=5/4 and

y-intercept (c)=12

Step-by-step explanation:

here,given equation of a line is

5x-4y-1=0...eqn(i)

equation of any line parallel to line(i) is

5x-4y+k=0...eqn(ii)

since,the line(ii) passes through (-8,2)[replacing x=-8 and y=2 in eqn(ii), we get]

5*(-8)-4*2+k=0

or-40-8+k=0

•°•k=48

substituting the value of k=48 in eqn(ii),

5x-4y+48=0 is the required equation of the line.

now,

changing eqn(ii) in slope intercept form we get,

4y=5x+48

or,y=5x/4+48/4

or,y=(5/4)x+12

comparing it into y=mx+c we get,

slope(m)=5/4 and y-intercept(c)=12