PLEASE HELP What is the equation of the line that passes through the point (4, -4) and has a
slope of ?

Step-by-step explanation:

Using a point (4, -4) and the slope of the line that passes through it, m = -⁵/2, we can generate an equation by using the point-slope form equation of a line given as y - b = m(x - a).

Where,

(a, b) = (4, -4)

m = -⁵/2

Plug in the values

y - (-4) = -⁵/2(x - 4)

y + 4 = (-5x + 20)/2

Multiply both sides by 2

2y + 8 = -5x + 20

Subtract both sides by 8

2y = -5x + 20 - 8

2y = -5x + 12

Divide both sides by 2

y = -⁵/2x + 12/2

(equation in slope-intercept form)

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation: