A system of equations can be solved by elimination in the table below.
1
5x + 3y = 14
4...
Mathematics, 17.12.2020 07:00 melwamb
A system of equations can be solved by elimination in the table below.
1
5x + 3y = 14
4x - 2y = -2
2.
2(5x + 3y) = 2(14)
4x - 2y = -2
5x + 3y = 14
3(4x - 2y) = 3(-2)
3
10x + 6y = 28
4x - 2y = -2
5x + 3y = 14
12x - y = -6
4
10x + 6y = 28
12x - 6y = -6
Does the system of equations on line 4 have the same solution set as the system of equations on line
1? Why or why not?
Answers: 3
Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
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Answers: 1
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