A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, round to the nearest 100th of second . y=-16x^2+242x+73

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

u what ?

step-by-step explanation:

answer: -1

step-by-step explanation: