The diagonals of quadrilateral ABCD intersect at E. If EC = 4 , BD =12, AE=x, and BE =y, what values of x and y would prove that the quadrilateral is a parallelogram? A. X=4; Y=6

B. X=4; Y=12

C. X=8; Y=6

D. X=8; Y=12

Need help ASAP Pleas

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

a

step-by-step explanation:

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answer: correct

step-by-step explanation:

you can not solvr this without numbers