A model for a company's revenue from selling a software package is R(p) = -2.5p2+650 p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue. PLEASEEE HELP NOWW
The price $
nothing maximizes the revenue.
(Simplify your answer.)

The maximum revenue is $
nothing.
(Simplify your answer.)

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

no one knows lol

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204