r = −3 cos(θ)
r = 3 cos(θ)
Mathematics, 16.12.2020 09:30 mayratrejorod3
What is the polar form of (x + 3)2 + y2 = 9?
r = −6 cos(θ)
r = −3 cos(θ)
r = 3 cos(θ)
r = 6 cos(θ)
Answers: 2
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What is the polar form of (x + 3)2 + y2 = 9?
r = −6 cos(θ)
r = −3 cos(θ)
r = 3 cos(θ)
r = −3 cos(θ)
r = 3 cos(θ)
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