If quinn tosses a fair coin and then rolls a fair number cube labeled 1 through 6, what is the probability of tossing heads followed by rolling a number less than three a. 3/12
b.2/12
c.2/16
d.1/12

B) 2/12 basically 1/6 but not simplified

Step-by-step explanation:

so the probability of flipping heads is 1/2

The probality of rolling a number LESS than 3 is 2/6 becuase there are only 2 numbers less then 3 on a 1-6 cube.

now multiply them

1/2*2/6

2/12

so B

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

42.4

step-by-step explanation:

convert to decimal