Y= -2 (x+2)^2-8
vertex=?
how to graph?

For
y=a(x-h)^2+k
vertex is (h,k)
a tells about the graph

y=-2(x-(-2))^2-(-8)
vertes ix (-2,-8)

to graph, plot some points
when x=0, then y=-16
(0,-16)
when x=1, then y=
(1,-26
when x=-1, then y=-10
(-1,10)
when x=-3, y=-10
(-3,10)

Where is the qeustion