The animal shelter had a special on adoption rates for their dogs and cats. Each dog adoption fee was $75 and each cat adoption fee was $35. On Christmas Eve, the animal adopted out 8 total animals and brought in $400 in total adoption fees. How many dogs and how many cats were adopted out on Christmas Eve? dogs:

cats:

3 dogs and 5 cats were adopted out on Christmas eve.

Step-by-step explanation:

Let the number of dogs adopted out on Christmas eve be x and the number of cats be y.

From the question,

On Christmas Eve, the animal adopted out 8 total animals

That is, x + y = 8 (1)

and brought in $400 in total adoption fees.

Also from the question,

Each dog adoption fee was $75 and each cat adoption fee was $35.

∴ On Christmas Eve,

75x + 35y = 400 (2)

Now, to determine how many dogs and how many cats were adopted out on Christmas Eve, we will solve the two equations simultaneously.

From equation (1)

x + y = 8

Make x the subject of the relation.

∴ x = 8 - y (3)

Substitute the value of x into equation (2)

75(8 - y) + 35y = 400

600 - 75y + 35y = 400

600 -40y = 400

600 - 400 = 40y

200 = 40y

∴ 40y = 200

y = 200/40

y = 5

Substitute the value of y into equation (3)

x = 8 - y

x = 8 - 5

x = 3

∴ x = 3 and y = 5

Hence, 3 dogs and 5 cats were adopted out on Christmas eve.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

the radius is 2 times the diameter.

step-by-step explanation: