Use the coordinates of the labeled point to find the point slope equation of the line.

B

Step-by-step explanation:

Here, we want to find the point-slope equation of the line

We start by getting the y-intercept of the line which is y = 3

The general equation of a straight line is;

y = mx + b

where b is the y-intercept

So, we have;

y = mx + 3

Now, to get m , we insert the point given on the like which is (2,-5)

x = 2 and y = -5

-5 = 2m + 3

-8 = 2m

m = -8/2

m = -4

So the equation of the line is;

y = -4x + 3

This is same as option B

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)