What additional information could be used to prove ABC MQR using SAS?

To prove that ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.

From the diagram, it is shown that CA is congruent to RM.

From the first option, given that m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = m∠M = 64°).

This shows that the first option is correct.

From the second option, given that CB = MQ = 29 cm, then we have CA = RM, CB = MQ, but ACB is not congruent to RMQ.

Thus the second option in not correct.

From the third option, m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60°, but we do not know the value of MRQ.

Thus the third option is not correct.

From the fourth option, m∠R = 60° and AB ≅ MQ, then we have CA = RM, AB = MQ, RMQ = 64°, but we do not know the value of CAB.

Thus the fourth option is not correct.

From the fifth option, AB = QR = 31 cm, then we have CA = RM, AB = QR, but we do not know the value of CAB or MRQ.

Thus, the fifth option is not correct.

Therefore, the additional information that could be used to prove ΔABC ≅ ΔMQR using SAS is m∠A = 64° and AB = MQ = 31 cm

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

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step-by-step explanation: