How to convert To prepare for a bake-off, Louise used 0.61 kilogram of flour each day for 3 weeks. How many grams did Louise use in those 3 weeks? 1 kg = 1,000 g

Given:

Louise used 0.61 kilogram of flour each day for 3 weeks.

To find:

How many grams did Louise use in those 3 weeks?

Solution:

We know that,

1 kg = 1000 g

Flour used by Louise each day for 3 weeks = 0.61 kg

1 week = 7 days

3 week = 21 days

Flour used by Louise for 3 weeks (21 days) = (21 × 0.61) kg

                                                                        = 12.81 kg

                                                                        = (12.81 × 1000)    [ 1 kg = 1000 g]

                                                                        = 12810 g

Therefore, flour used by Louise for those 3 weeks is 12,810 grams.

constant of proportionality = 3 and the equation is c = 3p.

step-by-step explanation:

c = kp   where c = amount of caffeine in mg., p = oz of pepsi and k is the constant of proportionality.

substituting the values given:

24 = 8k

k = 3.

the same value of k will be obtained if we substitute the other given values.

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct