What is the value of arccos(sine (StartFraction pi Over 2 EndFraction))?

0 radians or 2π radians

Step-by-step explanation:

arccos(sine (StartFraction pi Over 2 EndFraction)) is expressed as;

cos^(-1) (sin π/2)

Now, (sin π/2) in radians is same as (sin 180/2) = sin 90 in degrees.

Thus;

(sin π/2) = 1

Thus;

cos^(-1) 1 = 0

It could also be 360° in the fourth quadrant since cosine is positive there too.

Thus,

cos^(-1) (sin π/2) = 0° or 360°

In radians, this gives; 0 radians or 2π radians

ian gone lie this got me confused

step-by-step explanation: