Solve the system using substitution.
y + 8x = 10
2y - 4x = 40
(-1, [?])

Solve for

y

in the first equation.

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y

=

−

20

+

4

x

−

2

x

−

2

y

=

10

Replace all occurrences of

y

in

−

2

x

−

2

y

=

10

with

−

20

+

4

x

.

y

=

−

20

+

4

x

−

2

x

−

2

(

−

20

+

4

x

)

=

10

Simplify

−

2

x

−

2

(

−

20

+

4

x

)

.

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y

=

−

20

+

4

x

−

10

x

+

40

=

10

Solve for

x

in the second equation.

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y

=

−

20

+

4

x

x

=

3

Replace all occurrences of

x

in

y

=

−

20

+

4

x

with

3

.

y

=

−

20

+

4

(

3

)

x

=

3

Simplify

−

20

+

4

(

3

)

.

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y

=

−

8

x

=

3

The solution to the system of equations can be represented as a point.

(

3

,

−

8

)

The result can be shown in multiple forms.

Point Form:

(

3

,

−

8

)

Equation Form:

x

=

3

,

y

=

−

8

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1

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