Please help me I’m so confused

60

Step-by-step explanation

Okay, uh... this is gonna be confusing to explain.

So a hexagon's angles add up to 720. This means, we can find each angle's supplementary angle by subtracting each value we know away from the total.

So, we know the inside angle of angle 6 is 90.

So: 720-90=630

Now, typically, you would divide by the remaining angles, but we have basically 2 angles of different values since 1, 2, and 3 are equal, and 4 and 5 are equal.

However, we know that 1, 2, and 3 are 10 degrees less than 4 and 5. So if we "add" 10 degrees to each of those angles we get:

10*3=30

630-30=600

Now we made it as though each angle (1-5) is equal. So now we divide by 5.

600/5=120

This means the supplementary of angles 4 and 5 is 120, so we subtract that value from 180 since a straight angle is 180.

180-120=60

Now, to check this we reverse it.

(120*2)+(120*3)+(10*3)+(90)=

240+360+30+90=

600+30+90=

600+120=

720.

Um... I think this is it?? Your school is scary :o

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)