Find mQT

142

46

71

90

For purposes of this exercise,

x

represents the number homecoming tickets, and

y

represents the number of general admission sold.

A-The system of equations is:

x

+

y

=

150

5

x

+

8

y

=

900

B- Attachment

C- Let's solve this system of equations by elimination.

x

+

y

=

150

5

x

+

8

y

=

900

The first step will be multiply the first equation for -5, we will have

−

5

x

+

−

5

y

=

−

750

5

x

+

8

y

=

900

If we add both equations

x

will be eliminated and the new equation will be:

3

y

=

150

y

=

50

Replacing the value of

y

on the first equation, we have:

x

+

50

=

150

x

=

100

The solution is

(

100

,

50

)

D- To be a solution for the system of equations, it should be a solution for each equation in the system. Plugging

x

and

y

values in the first equation

x

+

y

=

150

180

−

30

=

150

s

o

l

u

t

i

o

n

For the second equation:

5

x

+

8

x

=

900

5

∗

180

+

8

(

−

30

)

=

900

900

−

240

≠

900

y

represents the number of tickets for general admissions, the numbers of tickets should not be a negative number.

a

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4