Find the sum or difference
(4y+3)-(y-2) do help me pls i can't remember how to do these

3y + 1

Step-by-step explanation:

(4y + 3) - (y - 2)

*subtract y from 4y because like terms must be combined*

3y + 3 - 2

*subtract 2 from 3*

3y + 1

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^