Graph the line with with a slope -1 passing through the point (3,3)

Y = mx + b
slope(m) = -1
(3,3)...x = 3 and y = 3
now we sub and find b, the y int
3 = -1(3) + b
3 = -3 + b
3 + 3 = b
6 = b

so ur equation of ur line is : y = -x + 6

so ur y int is (0,6)
ur x int can be found by subbing in 0 for y and solving for x
0 = -x + 6
x = 6so ur x int is (6,0)

so plot ur points(0,6) and (6,0)start at the y int (0,6) and since ur slope is -1, come down 1 space and go to the left 1, then down 1, and to the left 1, keep doing thisand u should cross the x axis at (6,0)