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Mathematics, 14.12.2020 23:00 Claude512

Using a directrix of y = 2 and a focus of (3, −4), what quadratic function is created? f(x) = one twelfth (x − 3)2 − 1 f(x) = −one sixth (x + 3)2 + 1 f(x) = one sixth (x − 3)2 + 1 f(x) = −one twelfth (x − 3)2 − 1

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Using a directrix of y = 2 and a focus of (3, −4), what quadratic function is created? f(x) = one tw...

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