Q10. What is the equation of the line that is perpendicular to the line y = -1/2x + 1, and goes through the point (3, 2). *
y = 2x + 1
y = x/2-4
y=-x/+ 1
y = -2x - 7
y = 2x - 4

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

77

step-by-step explanation:

answer: it's a

step-by-step explanation: