Choose the graph that represents the following system of inequalities: y ≥ −3x + 1
y ≤ 1 over 2x + 3

In each graph, the area for f(x) is shaded and labeled A, the area for g(x) is shaded and labeled B, and the area where they have shading in common is labeled AB.
a dashed line g of x rising left to right that is shaded below and a dashed line f of x that is falling left to right that is shaded above
a dashed line f of x rising left to right that is shaded above and a dashed line that is falling g of x left to right that is shaded above
a dashed line g of x rising left to right that is shaded above and a dashed line f of x that is falling left to right that is shaded below
a dashed line g of x rising left to right that is shaded below and a dashed line f of x that is falling left to right that is shaded below

Option B loves

Step-by-step explanation:

I took the test

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

a

step-by-step explanation: