Lucille has an aquarium with 9 gallons of water which weighs 85 pounds. The stand holding the aquarium can hold no more than 112 pounds. She wants to add 2.5-pound rocks, r, her tank. Complete the inequality to show how many rocks she can add. R≤

OR

Step-by-step explanation:

Given that:

Amount of water in the aquarium = 9 gallons

Weight of water in the aquarium = 85 pounds

Total weight that aquarium can hold = 112 pounds

Weight of each rock = 2.5 pounds

To find:

The inequality to find the number of rocks, that can put in her tank.

Solution:

First of all, let us find more weight that the aquarium can hold after putting the water in the aquarium.

Additional weight that can be put in the aquarium = Total weight - Weight of water = 112 - 85 = 27 pounds

This 27 pounds can be of rocks.

Let the number of rocks that can be put in the aquarium =

Total weight of number of rocks = Weight of one rock multiplied by =2.5

Now, this weight of rocks must be lesser than or equal to 27 pounds.

Therefore, the in equality is:

she gotta workk that a 2

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15