Find the H. C.F for 513, 1134 and 1215

Solution:

In this question no method is specified to find the H.C.F so

Here we find the H.C.F by Euclid division lemma:-

a=bq+r

Here a= 1215 , b = 1134

1215>1134>513

1215=1134(1)+81

1134=81(14)+0

remainder becomes 0,the Hcf of 1134 and 1215 is 81.

Then find the Hcf of 81 and 513

513=81(6)+27

81=27(3)+0

remainder becomes 0, HCF of 513 & 81 is 27.

Hence, the HCF of 513,1134 and 1215 is 27.

By Prime factorization method

1215= 3×3×3×3×3×5= 3^5 ×5¹

1134= 3×3×3×3×2×7= 3⁴×2¹×7¹

513= 3×3×3×19= 3³× 19¹

H.C.F= 3³= 3×3×3= 27

Hence, the HCF of 513,1134 and 1215 is 27.

Hope this will help you

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc