Guys anyone please help . Please explain how to solve these questions it gives the answers but I need expiation (Calculus) ,I’ll give brainliest for the correct answer ! Pleasseee

9514 1404 393

  (ii) center: (-3, 6)

  (iii) A(-3, 6-√51), B(7, 6), D(-3, 6+√51), H(-13, 6)

  (iv) (x +3)²/100 +(y -6)²/51 = 1

Step-by-step explanation:

(ii) The center is the midpoint between the foci:

  center = ((-10, 6) +(4, 6))/2 = (-10+4, 6+6)/2

  center = (-3, 6)

__

(iii) The vertices are the center plus or minus the semi-major axis length in the x-direction: (-3±10, 6).

The semi-minor axis length is the root of the difference of squares of the semi-major axis and the center-focus distance:

  semi-minor axis = √(10² -7²)

  semi-minor axis = √51

So, the co-vertices are the center plus or minus this value in the y-direction: (-3, 6±√51)

Using the labeling in the drawing the various points are ...

  A(-3, 6-√51), B(7, 6), D(-3, 6+√51), H(-13, 6)

__

(iv) For center (h, k) and semi-axis lengths 'a' and 'b' the equation of an ellipse is ...

  (x -h)²/a² +(y -k)²/b² = 1

For the center and axes here, the equation is ...

  (x +3)²/100 +(y -6)²/51 = 1

false

step-by-step explanation:

false.   two legs of the trapezoid would be congruent, but the other two would not.   were all the legs congruent, then we'd have a square; were the 2 shorter sides congruent and the 2 longer sides also congruent, we'd have a rectangle.

dont think so

step-by-step explanation: