You need to paint a decorative garden ornament that is in the shape of pyramid with a square base that is 9 inches long and has a slant height of 12 inches.

a. A smaller pyramid has linear dimensions that are

times that of the larger pyramid. Does the

smaller pyramid require times the amount of paint? Explain.

b. Another pyramid has the same base lengths but the slant height. Does this pyramid require

the paint as the original pyramid? Explain.

Step-by-step explanation:

Total Surface area of a pyramid is given as

= Lateral surface area + area of base.

Lateral surface area = 1/2×perimeter of base×slant height

given the base is square with side 9 in , and slant height of 12 inches.

therefore, LSA = 1/2(9*4)×12 = 216 in^2

Now, TSA = LSA + Base area = 216+9^2 = 297 in^2

a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).

b) It can not be solved as dimensions are missing in the question.

However, the logic has been explained in the soluion one easily put values to find the solution.

4th option is correct xy=-10

if this was to u plzz mark me the brainliest

d is the answer

step-by-step explanation: