Please help.

a. 754cm³ (3 s.f.)

b. 415cm² (3 s.f.)

Step-by-step explanation:

Formulas (for easier reference):

Volume of cone: r²

Volume of hemisphere: r³

Surface area of cone without base: rl

Surface area of hemisphere without base: 2r²

We can just apply the formulas for the question:

Volume of toy = ( × 6² × ) + ( × 6³)

                        = 96 + 144

                        = 240

                        = 754cm³ (3 s.f.)

Surface area of toy = ( × 6 × 10) + (2 × × 6²)

                                = 60 + 72

                                = 132

                                = 415cm² (3 s.f.)

it is b)

hope this : )

step-by-step explanation:

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: