Solve the equation 18y-6y+22=11(y-2)+y

the answer its 44=0

Step-by-step explanation:

18y-6y+22=11(y-2)+y1

We move all terms to the left:

18y-6y+22-(11(y-2)+y1)=0

We add all the numbers together, and all the variables

12y-(11(y-2)+y1)+22=0

We calculate terms in parentheses: -(11(y-2)+y1), so:

11(y-2)+y1

We add all the numbers together, and all the variables

y+11(y-2)

We multiply parentheses

y+11y-22

We add all the numbers together, and all the variables

12y-22

Back to the equation:

-(12y-22)

We get rid of parentheses

12y-12y+22+22=0

We add all the numbers together, and all the variables

44=0

are not solution for this equation

Hope helps you and have a great day !

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7