Please pleas help me!! Solve the system using elimination.

6x + 14y = 32
6x - 14y = 4

The solution is ___ ( simplify your answer. Type an ordered pair.)

x = 3 and y = 1

Step-by-step explanation:

The given equations are :

6x + 14y = 32  ...(1)

6x - 14y = 4 (2)

Add equation (1) and (2) :

6x + 14y + 6x - 14y = 32 + 4

12x = 36

x = 3

Put the value of x in equation (1)

6(3) + 14y = 32

18 + 14y = 32

14y = 32-18

14y = 14

y = 1

Hence, the value of x is 3 and y is 1.

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