Water is flowing into and out of a small reservoir. The total amount of water can be modeled by R, where sin cubic feet, t is measured in hours, and ≤ t ≤ 8. a) What is the average rate of change of R over the interval ≤ t ≤ 8? Indicate the correct units of measure. b) Find the value of R′ (t). Using correct units, interpret the meaning of the value in the context of the problem. c) Find all times t for which the rate at which the amount of water in the reservoir is changing is equal to the average rate of change of R over the interval ≤ t ≤ 8. d) The reservoir can hold a maximum of 30 cubic feet. At what time after t = 8 hours will the reservoir reach its capacity?

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer

11 feet 6 inches and 8 feet 6 inches

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15