How to write y-2=-1/3 (x+6) in standard form and why PLZ HELP

Simply move -2 to another side.

Distribute -1/3 in (x+6)

       ---> Answer

x + 3y = 0

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y - 2 = - (x + 6) ← distribute

y - 2 = - x - 2 ( add 2 to both sides )

y  = - x ( multiply through by 3 to clear the fraction )

3y  = -  x ( add x  to both sides )

x + 3y = 0 ← in standard form

answer for #1 is c

answer for #2 is d

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-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a