What values of a, b,c make this equation true? (2x-5)(x+2)+(ax^2+bx+c)=6x^2-4x-7

A - a = 4, b = -3, c = 3

Step-by-step explanation:

When you substitute in a, b, and c you get

(2x - 5) (x + 2) + (4x^2 + -3x + 3)

collect like terms

(2x)(x) + (2x)(2) + (−5)(x) + (−5)(2) + 4x^2 + −3x + 3

combine like terms

2x^2 + 4x + −5x + −10 + 4x^2 + −3x + 3

(2x^2 + 4x^2) + (4x + −5x + −3x) + (−10 + 3)

6x^2 + −4x + −7

6x^2 + −4x −7

where is the page?

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )