How do I solve this, please help

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Step-by-step explanation:

Since EH is the perpendicular bisector of DF, ∆DEF is isosceles and sides DE and EF have the same length.

  DE = EF

  (9x -1) = (7x +9)

  2x = 10 . . . . . . . add 1-7x

  x = 5 . . . . . . . . . divide by 2

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Similarly, marked sides GD and GF are the same length, so ...

  GD = GF

  (10y -4) = (7y +8)

  3y = 12 . . . . . . . . . . add 4-7y

  y = 4 . . . . . . . . . divide by 3

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Now, we have what we need to calculate the side lengths.

  EF = 7x+9 = 7·5 +9 = 44

  DE = 9x-1 = 9·4 -1 = 44

  FG = 7y+8 = 7·4 +8 = 36

  DG = 10y-4 = 10·4 -4 = 36

  FH = 3x+4y = 3·5 +4·4 = 31

  DF = FH = 31

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

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step-by-step explanation: