Line segment AC is given by A (-3,6) and B (6,9). Find the coordinates of point B such that AB:BC is 2:1 Please help now

(0, 7)

Step-by-step explanation:

Using the midpoint formula expressed as;

M (X, Y )= [(ax1+bx2/a+b), (ay1+by2/a+b)]

where a and b are the ratios

Given

a = 2

b = 1

x1 = -3

y1 = 6

x2 = 6

y2 = 9

Get the coordinate of B

Get X;

X = ax1+bx2/a+b

X = 2(-3)+1(6)/2+1

X = -6+6/3

X = 0/3

X = 0

Get Y;

Y = ay1+by2/a+b

Y = 2(6)+1(9)/2+1

Y = 12+9/3

Y = 21/3

Y = 7

Hence the coordinate of B is (0, 7)

597

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4