Which postulate or theorem can be used to prove that AABC = ADCB?
SSS
ASA
SAS
AAS

SSS congruency criteria can be used here to prove ∆ABC ≅ ∆DCB

In ∆ABC and ∆DCB

AB = CD (given)

AC = BD (given)

BC = BC (common)

So, by SSS congruency criteria,

∆ABC ≅ ∆DCB

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.