Find the perimeter of (JHS) with mid segments AB=5.4 and AC=4

the perimeter of triangle JHS is 24.8

Step-by-step explanation:

basically its a lot of explanation and work but you can find the sides by using the midpoint theorem since AB and AC are midpoints. this means that triangle JHS is double the size of triangle AHB. So they share all the same angles but all the sides are half of JHS. And then through parallel lines and vertical angles you can find everything you need.

sorry thats a bad explanation but let me know if you want me to go into detail on how I solved it

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4