What is the period of y = sin(3x)?

sin 3 x = sin ( 3 x + 2 π ) = sin [ 3 ( x + 2 π/ 3 ) ] = sin 3 x

This means "after the arc rotating three time of ( x + ( 2  π /3 ) ) , sin 3x comes back to its initial value"

So, the period of sin 3x is 2 π /3 .

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3