The exterior angles of a triangle measure x + 3, 2x + 1, and 3x - 4. find the measure of each exterior angle

63, 121 and 176. All angles in degree

Step-by-step explanation:

The exterior angles of the triangle added to their corresponding interior angles equal 180 degrees by virtue of the sum of angles on a straight line.

As such the interior angles are

1. 180 - (x+ 3)

2. 180 - (2x+ 1)

3. 180 - (3x - 4)

Given that the sum of angles in a triangle is 180 degrees

180 - (x+ 3) +  180 - (2x+ 1) + 180 - (3x - 4) = 180

540 - 6x = 180

6x = 540 - 180

6x = 360

x = 60

The exterior angles are

x + 3 = 60 + 3 = 63

2x + 1 = 2(60) + 1 = 121

and

3x - 4 = 3(60) - 4 = 180  - 4 = 176

the one below it is a function

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west