Solve: 16 > 4(z - 7)
A. z 11
C. z 13

z

≤

11

Explanation:

Perform the necessary mathematics to isolate and solve for  

z

while keeping the inequality balanced:

First, expand the terms within parentheis:

16

≥

(

4

⋅

z

)

−

(

4

⋅

7

)

16

≥

4

z

−

28

Next, add 28 to both sides of the inequality:

16

+

28

≥

4

z

−

28

+

28

44

≥

4

z

−

0

44

≥

4

z

Then, divide each side of the inequality by 4:

44

4

≥

4

z

4

11

≥

(

4

4

)

z

11

≥

1

z

11

≥

z

Finally, "flip" the inequality to put the answer in terms of  

z

z

≤

11 theres that

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

70.30

step-by-step explanation: