PLEASE HELP ME I AM TIMED ONLY HAVE !% more minutes :( PLEASE I WILL GIVE BRAINIEST Table sugar is sucrose (C12H22O11). Determine the percentage composition by mass of sucrose.?

Look up the atomic masses of each element in sucrose:

• C has an atomic mass of 12.011 u

• H has an atomic mass of 1.008 u

• O has an atomic mass of 15.999 u

Sucrose consists of 12 C atoms, 22 H atoms, and 11 O atoms, so one molecule has an atomic mass of about

12 (12.011 u) + 22 (1.008 u) + 11 (15.999 u) ≈ 342.3 u

Then

• C makes up (12 (12.011 u)) / (342.3 u) ≈ 0.4211 = 42.11%,

• H makes up (22 (1.008 u)) / (342.3 u) ≈ 0.06479 = 6.479%, and

• O makes up (11 (15.999 u)) / (342.3 u) ≈ 0.5141 = 51.41%

of sucrose

your answer is d 2,500

step-by-step explanation: