The altitude of an airplane is decreasing at a rate of 42 ft per second what is the change in altitude of the airplane over a. Of 22 seconds

Over a 22 seconds, the altitude will be: 924 feet

Step-by-step explanation:

As the altitude of an airplane is decreasing at a rate of 42 ft per second.

Thus, the expression to find the altitude at x seconds is:

y = 42x

so at x = 1 sec, y = 42 feet

Now, putting x = 22 seconds to determine the altitude at 22 seconds

y = 42x

  = 42(22)

  = 924 feet

Thus, over a 22 seconds, the altitude will be: 924 feet

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: