Which system of equations has exactly one solution? O 2x+y=3
5x-y=11
O 2x+2y = 1
-2x-2y = 1
o =
3x+y=-1
6x+2y = -2
3x-2y=4
-3%+ 2y =4

shsdkrtyl

Step-by-step explanation:

down one may be

Step-by-step explanation:

lasted one

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

about 168 miles

step-by-step explanation: