A car park has no parking spaces on the first floor. The second floor has double the amount of spaces on the first floor. The third floor has 3 more spaces than the second. The total number of spaces is 428. Use an algebraic method to work out the number of parking spaces on the first floor.

85 parking spaces

Step-by-step explanation:

Given that :

Parking spaces on floors :

Let first floor = x

Second floor = 2x

Third floor = 2x + 3

Total parking spaces = 428

THEREFORE ;

x + 2x + 2x + 3 = 428

5x + 3 = 428

5x = 428 - 3

5x = 425

x = 425 / 5

x = 85

Hence, there are 85 parking spaces on the first floor

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !