Alice is making balloon bunches from 36 red balloons and 16 blue balloons. She wants the same number of red balloons and the same number of red balloons in each bunch. What is the greatest number of balloons bunches Alice can make using all the balloons? How many red and blue balloons will be in each bunch?

a) The greatest number of balloon bunches she can have is 4 ballon Bunches

b) 9 red ballons and 4 blue ballons in each bunch.

Step-by-step explanation:

Alice is making balloon bunches from 36 red balloons and 16 blue balloons. She wants the same number of red balloons and the same number of red balloons in each bunch.

a) What is the greatest number of balloons bunches Alice can make using all the balloons?

We solve using Greatest Common Factor Method

We find the factors of 16 and 36

The factors of 16 are: 1, 2, 4, 8, 16

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

Then the greatest common factor is 4.

Hence, the greatest number of balloon bunches she can have is 4 ballon Bunches

b) How many red and blue balloons will be in each bunch?

This is calculated as:

For red ballons = she has 36

= 36 ballons/ 4 ballon bunches = 9 red ballons in each bunch

For blue ballons = she has 16

= 16 ballons/4 ballon bunches = 4 blue ballons in each bunch

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40