Determine which equation is parallel to line JK and which is perpendicular to line JK. 6x + 10y = 11 6x - 10y = 7 5x - 3y = 8 5x + 3y = 13 -10 -8 H6 4 -2 -10 -8 -6 -4 -2 2 4 6 8 10 -2 o K -6 -8 10 Parallel Line Perpendicular Line

1/5^2 = 7.56/45

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

48 / 6 = x

in this case, x will equal the amount of money in each card!

x therefore will be 8.

trent had $8 in each birthday card.