Given a term in an arithmetic sequence and the common difference, find the first five terms 1) a17 = 71, d = 6

I need the answer fast and if you can, please explain.

Step-by-step explanation:

To find the first five terms

we come with a1

a(n) = a1 +(n-1)d

a(17) = a1 +(17-1)6=71

 So a1=71-96= -25  

first five terms:

a1= -25

a(2) = -25 +(2-1)6=-19

a(3) = -25 +(3-1)6=-13

a(4) = -25 +(4-1)6=-7

a(5) = -25 +(5-1)6=-1

hope it helps

the graph on the bottom right

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.