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(4,0) and (1,-3) are the solutions sets.

Step-by-step explanation:

Given that:

y = x²-4x       Eqn 1

y = x - 4        Eqn 2

In substitution method, the equation is solved for one variable and then put in the other.

Putting value of y from Eqn 2 in Eqn 1

x - 4 = x²- 4x

Adding -x+4 on both sides

Factorizing the equation;

Either,

x-4 = 0,     => x=4

Or,

x-1=0,       => x=1

Putting x=4 in Eqn 2

y = 4-4

y = 0

Putting x=1 in Eqn 2

y = 1-4

y = -3

Hence,

(4,0) and (1,-3) are the solutions sets.

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true