Mathematics, 10.12.2020 01:10 mrus

HELP The formulas are:

sin2u = 2sinx cosx

tan2u = 2tanu / 1 - tan^2u
= sin2u / cos2u

cos2u = cos^2u - sin^2u
= 2cos^2u - 1
= 1 - 2sin^2u

HELP

The formulas are:
sin2u = 2sinx cosx
tan2u = 2tanu / 1 - tan^2u
= sin2u / cos2u
cos2u =

Answers: 3

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HELP The formulas are:

sin2u = 2sinx cosx

tan2u = 2tanu / 1 - tan^2u
...